Respuesta :

B. If [tex]p[/tex] is true, then [tex]\sim p[/tex] (NOT [tex]p[/tex]) is false; If [tex]q[/tex] is false, then [tex]\sim q[/tex] is true. Then [tex]\sim p\land\sim q[/tex] must be false, because both arguments are not true.

Answer with Step-by-step explanation:

p is true then ~p is false.

q is false then ~q is true.

A. p -> q

if p is true and q is false then this gives false truth value.

Hence, here truth value is F

B. ~p/\~q

if any one of them is false then it gives false truth value.

Hence, here truth value is F(since,~p is false)

C. p->~q

true statement implies a true statement hence, truth value will be true

Hence, here truth value is T(p true implies ~q true)

D. q\/~p

if any one of them is true then compound statement is true.

Hence, here truth value is F(since, ~p and q both are false)

E. p/\~q

if both true then compound statement is also true.

Hence, here truth value is T(since p and ~q both are true)

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