Respuesta :
B. If [tex]p[/tex] is true, then [tex]\sim p[/tex] (NOT [tex]p[/tex]) is false; If [tex]q[/tex] is false, then [tex]\sim q[/tex] is true. Then [tex]\sim p\land\sim q[/tex] must be false, because both arguments are not true.
Answer with Step-by-step explanation:
p is true then ~p is false.
q is false then ~q is true.
A. p -> q
if p is true and q is false then this gives false truth value.
Hence, here truth value is F
B. ~p/\~q
if any one of them is false then it gives false truth value.
Hence, here truth value is F(since,~p is false)
C. p->~q
true statement implies a true statement hence, truth value will be true
Hence, here truth value is T(p true implies ~q true)
D. q\/~p
if any one of them is true then compound statement is true.
Hence, here truth value is F(since, ~p and q both are false)
E. p/\~q
if both true then compound statement is also true.
Hence, here truth value is T(since p and ~q both are true)