Question

How many hydrogen atoms are in 2.80 mol of ammonium sulfide?

Answer 1

You can see each (NH4)2S has 
2 N atoms 
8 H atoms 
1 S atom 

So moles H atoms = 8 x moles (NH4)2S 
= 52.0 moles H 

1 mole anything = 6.022x10^23 units of that anything 

So number H atoms = moles H atoms x 6.022x10^23 atoms/mol 
= 52.0 x 6.022x10^23 atoms/mol 
= 3.13x10^25 atoms of H

Answer 2

Answer : The number of hydrogen atoms are, $134.89\times 10^{23}$

Explanation : Given,

Moles of hydrogen atoms = 2.80 mole

As we know that, the formula of ammonium sulfide is, $(NH_4)_2S$. In ammonium sulfide, there are 2 atoms of nitrogen, 8 atoms of hydrogen and 1 atom of sulfur.

Now we have to calculate the number of hydrogen atoms.

As, 1 mole of $(NH_4)_2S$ contains $8\times 6.022\times 10^{23}$ number of hydrogen atoms.

So, 2.80 mole of $(NH_4)_2S$ contains $2.80\times 8\times \times 6.022\times 10^{23}=134.89\times 10^{23}$ number of hydrogen atoms.

Therefore, the number of hydrogen atoms are, $134.89\times 10^{23}$