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In gym class you run 22 m horizontally, then climb a rope vertically for 6.2 m. What is the direction angle of your total displacement, as measured from the horizontal?
Express your answer using two significant figures and include the appropriate units.

Respuesta :

Im 99% sure
tan^-1 (6.2/22)= 15.7º
with 2 significant figures 16º

Answer:

[tex]\theta = 16 degree[/tex]

Explanation:

Displacement in horizontal direction(d) = 22 m

displacement in vertical direction(h) = 6.2 m

As we know that total displacement is the straight line which joins the initial position and final position of the object

so here we will have

[tex]tan\theta = \frac{h}{d}[/tex]

now plug in all data in it

[tex]tan\theta = \frac{6.2}{22}[/tex]

[tex]\theta = tan^{-1}(0.282)[/tex]

[tex]\theta = 15.74 degree[/tex]

since we have to give the answer in two significant digit so it is

[tex]\theta = 16 degree[/tex]

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