Respuesta :

well, we know x^(1/2) = √(x^1)

so, by that logic we know when a number n is raised to some fraction(x/y) then the numerator is the number n is raised to under the (denomenator) yth root.

So, the third root of 128^x= 128^(x/3)
Also, if we divide 128 by 4^3(64) we get 2. doing this allows us to put 4 outside the 3rd root and leave 2^x under the third root.

I would say the first, 3rd, and 4th answers should be correct and all equivilant to the third root of 128^x. (raising a number to (1/3) is = to taking the 3rd root of that number. this is why 3&4 are both equal)

The given expression can be evaluated by the help of arithmatic operations and the expression can be written as [tex](128)^{\frac{x}{3}}[/tex], [tex](4\sqrt[3]{2} )^x[/tex] and [tex](4 \times (2)^{\frac{1}{3}})^x[/tex].

Given :

Expression - [tex]\sqrt[3]{128^x}[/tex]

Arithmatic operations can be used to evaluate the given expression. The steps to evaluate the expression are as follows:

  • Step 1 - Rewrite the given expression.

        [tex]= (128)^{\frac{x}{3}}[/tex]

  • Step 2 - Rewrite 128 as [tex]2\times 2^6[/tex]

        [tex]=(2\times 2^6)^{\frac{x}{3}}[/tex]

  • Step 3 - Rearrange the given expression.

        [tex]= ((2\times2^6)^{\frac{1}{3}})^x = ((2)^{\frac{1}{3}}\times (2^6)^{\frac{1}{3}})^x[/tex]

  • Step 4 - Now,  [tex](2^6)^{\frac{1}{3}}[/tex]  becomes [tex]2^2[/tex] .

        [tex]=( 2^2 \times 2^{\frac{1}{3}})^x[/tex]

        [tex]= (4\times \sqrt[3]{2} )^x[/tex]

Therefore, the correct option is A), C), and D).

For more information, refer the link given below

https://brainly.com/question/22687297