Question

please help to solve the equations!

1) 3(k+5)=-2(3k-6)

2)1/2r+4=3/4r-3/2

3)2a-9=2a+5

4)8m+2+4m=2(6m+1)

Answer 1

1)3(k+5)=-2(3k-6)
3k+15=-6k+12
3k=-6k+12-15
3k=-6k-3
3k+6k=-3
9k=-3
k=-3/9=-1/3
so, k=-1/3
2)1/2r+4=3/4r-3/2
1/2r=3/4r-3/2-4
1/2r=3/4r-11/2
1/2r-3/4r=-11/2
-r/4=-11/2
4*(-r/4)=4*(-11/2)
-r=-22
r=22
3)2a-9=2a+5
2a=2a+5+9
2a=2a+14
2a-2a=14
0=14
no solution
4)8m+2+4m=2(6m+1)
12m+2=12m+2
12m=12m+2-2
12m=12m
12m-12m=0
0=0
true for all m