Question

a 5.00 × 105 kg rocket is accelerating straight up. Its engines produce 1.50 × 107 of thrust, and air resistance is 4.50 × 106 N. What is the rocket’s acceleration?

Answer 1

This one is simple :)

use the equation F = ma and then re-arrange for a.

a = F / m

But there is a trick, so be careful. the question gives you wind resistance. Simply subtract the wind resistance from the thrust of the rocket to get the net force upward.

$1.50 * 10^7N - 4.5 8 10^6N = 1.05 * 10^7N$

So,

$a = \frac{F}{m} = \frac{1.05*10^7N}{5.00*10^5kg}$

Answer 2

The rocket’s acceleration is $21m/s^2$

What is acceleration?

Acceleration is the rate of change of the velocity of an object with respect to time. Acceleration is vector quantities as it has both magnitude and direction.

It is given by

$a = \frac{v_f-v_0}{t}$

Where,

$a =$ average acceleration

$v_f=$ final velocity

$v_0=$ starting velocity

$t =$ elapsed time

What is Thrust?

The force acting on an object perpendicular to the surface is called thrust. It is vector quantity and SI Unit of thrust is Newton.

$\mathbf{T}=\mathbf{v} \frac{\mathrm{d} m}{\mathrm{d} t}$

Where,

$T=$ thrust

$v=$ velocity

$dm=$ change of mass

$dt=$ change in time

Given,

Mass of rocket, $m = 5*10^5Kg$

Thrust,$T = 1.5*10^7N$

Air resistance $F_a= 4.5*10^6N$

The net upward force will be

$F_n= T-F_a\\F_n= 1.5*10^7-4.5*10^6\\F_n= 1.05*10^7N$

Using

$F = ma\\a = \frac{F}{m}\\a = \frac{1.05*10^7}{5*10^5}\\a = 21 m/s^2$

Thus the acceleration is $21m/s^2$.

To learn more about acceleration here

brainly.com/question/2303856

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