Respuesta :

[tex]f(x) = \frac{3x - 12}{5} \\y = \frac{3x - 12}{5} \\5(y) = 5(\frac{3x - 12}{5}) \\5y = 3x - 13 \\5x = 3y - 13 \\5x + 13 = 3y \\\frac{5x + 13}{3} = \frac{3y}{3} \\1\frac{2}{3}x + 4\frac{1}{3} = y \\1\frac{2}{3}x + 4\frac{1}{3} = f^{-1}(x)[/tex]
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