Question

how do I convert

3$x^{2}$ - 20x - 7 = 0

into the form it was before distribution:

( ) ( ) = 0

Answer 1

$3x^2-20x-7=0\\ 3x^2+x-21x-7=0\\ x(3x+1)-7(3x+1)=0\\ (x-7)(3x+1)=0\\ x=7 \vee x=-\dfrac{1}{3}$