The relationships between the sides and angles of the right triangles in
the question are given by trigonometric ratios.
Correct responses;
- [tex]\displaystyle 2. \hspace{0.3 cm}\frac{4}{3}[/tex]
- [tex]\displaystyle 3. \hspace{0.3 cm}\frac{3}{5}[/tex]
- [tex]\displaystyle 4. \hspace{0.3 cm}\frac{7}{25}[/tex]
Methods used to arrive at the above responses;
1. The given triangle is ΔABC
The side opposite angle B is the side not bearing the letter B which is the side AC
2. The tangent of the angle, F, is given by the following formula;
[tex]\displaystyle tan(F) = \mathbf{\frac{Opposite \ side \ to \ angle \ F}{Adjacent \ side \ to \ angle \ F}}[/tex]
Therefore;
- [tex]\displaystyle \underline{ tan(F) = \frac{4}{3}}[/tex]
3. The sine of the angle Z is given by the following formula;
[tex]\displaystyle sin (Z) = \mathbf{ \frac{Opposite \ side \ to \ angle \ Z}{Hypotenuse \ side \ of \ right \ triangle}}[/tex]
Therefore;
[tex]\displaystyle sin(Z) = \mathbf{\frac{XY}{40}}[/tex]
XY = √(40² - 32²) = 24
Which gives;
- [tex]\displaystyle \underline{sin(Z) = \frac{24}{40} = \frac{3}{5}}[/tex]
4. The trigonometric ratio for cos(D) is given as follows;
[tex]\displaystyle cos(D) = \mathbf{ \frac{Adjacent \ side \ to \ angle \ \angle D}{Hypotenuse \ side \ of \ right \ triangle}}[/tex]
Therefore;
[tex]\displaystyle cos(D) = \frac{21}{75} = \frac{7}{25}[/tex]
- [tex]\displaystyle \underline{ cos(D) = \frac{7}{25} }[/tex]
5. The tangent of the angle 63° is expressed as follows;
[tex]\displaystyle tan(63^{\circ}) = \mathbf{\frac{8 \, m}{Distance \ AB \ (ground \ distance \ from \ wall)}}[/tex]
Therefore;
[tex]\displaystyle Distance \ AB = \frac{8 \, m}{tan(63^{\circ})} \approx \mathbf{4.076 \, m}[/tex]
- The approximate distance from the bottom of the ladder o the wall is 4 m
Learn more about trigonometric ratios here:
https://brainly.com/question/8517005