[tex] \frac{-2(7-10)^{2} }{-3} +1[/tex] equals 7.
First, simplify 7 - 10 to -3. Your problem should look like: -2 × [tex] \frac{(-3)^2}{-3} + 1[/tex].
Second, since the power of 2 is even, the result will be positive. Your problem should look like: -2 × [tex] \frac{3^2}{-3} + 1[/tex].
Third, simplify [tex] 3^{2} [/tex] to get 9. Your problem should look like: -2 × [tex] \frac{9}{-3} + 1[/tex].
Fourth, simplify -2 × [tex] \frac{9}{-3} [/tex] to 2 × [tex] \frac{9}{3} [/tex]. Your problem should look like: 2 × [tex] \frac{9}{3} [/tex] + 1.
Fifth, simplify 2 × [tex] \frac{9}{3} [/tex] to [tex] \frac{18}{3} [/tex]. Your problem should look like: [tex] \frac{18}{3} + 1[/tex].
Sixth, simplify [tex] \frac{18}{3} [/tex] to 6. Your problem should look like: 6 + 1.
Seventh, add 6 + 1. Your problem should look like: 7, which is your answer.