Question

Mike hiked to a lake in 6.5 hours at an average rate of 3 2/5 miles per hour. Pedro hiked the same distance at a rate of 3 4/5 miles per hour. How long did it take Pedro to reach the lake? Round to the hundredths place.

Answer 1

We first need to find the distance.
The information about Mike will provide the distance we need to answer the question about Pedro.

We will use D = rt

Mike:

(6.5)((17/5) = D

22.1 miles = D

Pedro:

D = rt

22.1 = (19/5)t

We need to find t.

22.1 ÷ 3.8 = t

5.8157894737 = t

We now round off as instructed.

5.82 = t

It took Pedro 5.82 hours to reach the lake.

Answer 2

Answer:

5.82 hours.

Step-by-step explanation:

We know that,

Distance = Time × Speed,

If the average rate of Mike = $3\frac{2}{5}$ miles per hour,

Time taken by him = 6.5 hours,

So, the distance he covered = $6.5\times 3\frac{2}{5}$

$=6.5\times \frac{17}{5}$

$=1.3\times 17$

$=22.1\text{ miles}$

If the average rate is $3\frac{4}{5}$ miles per hour to complete this distance,

Then time taken = $\frac{Distance}{Speed}$

$=\frac{22.1}{3\frac{4}{5}}$

$=\frac{22.1\times 5}{19}$

$=\frac{110.5}{19}$

≈ 5.82

Thus, the time taken by Pedro would be 5.82 hours.