Let
L--------> the length of the rectangle
W-------> the width of the rectangle
we know that
the perimeter of the rectangle is equal to
[tex]P=2L+2W[/tex]
[tex]P\leq 96\ cm[/tex]
so
[tex](2L+2W)\leq 96[/tex] ---------> equation [tex]1[/tex]
[tex]L=5W[/tex] ---------> equation [tex]2[/tex]
Substitute equation [tex]2[/tex] in equation [tex]1[/tex]
[tex]2*(5W)+2W\leq 96[/tex]
therefore
the answer is the option
2w+2⋅(5w)≤96