Question

what is the molality of a solution that has 3 mol of glucose in 6 kg of water?

Answer 1

it is 3/6 = 0.5 mol/kg of solvent i.e. 0.5 molal solution

Answer 2

Answer: 0.5 m

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

$Molality=\frac{n\times 1000}{W_s}$

where,

n= moles of solute

Moles of glucose = 3 moles

$W_s$ = weight of solvent (water) in g  = 6 kg = 6000 g   (1kg=1000g)

Now put all the given values in the formula of molality, we get

$Molality=\frac{3moles\times 1000}{6000g}=0.5mole/kg$

Therefore, the molality of solution will be 0.5 mole/kg.