Question

A jogger accelerates at a constant rate of 1.20 m/s^2 for 3.00 seconds. If her initial speed was 2.50 m/s, find her speed after those 3 seconds of acceleration.

Answer 1

Using:  v = u + at, 
u = initial speed = 2.50 m/s
a = acceleration = 1.2 m/s^2
t = time = 3.00 s

v = 2.5 + 1.2*3
v = 2.5 +3.6
v = 6.1

Her speed after 3s is 6.10 m/s.