Refer to the diagram shown below.
h = the height of the building
g = 9.8 m/s²
Wind resistance is ignored.
u = 22.2 m/s, horizontal velocity.
The initial vertical velocity is zero.
The time of flight, t, obeys the equation
h = (1/2)*g*t²
That is,
h = 0.5*(9.8 m/s²)*(t s)² = 4.9t²
[tex]t= \sqrt{ \frac{h}{4.9} } =0.4518 \sqrt{h} [/tex]
Because the horizontal distance traveled is 36.0 m, therefore
(22.2 m/s)*(0.4518√h) = 36.0
10.03√h = 36
√h = 3.5892
h = 12.882 m
Answer: 12.9 m (nearest tenth)
