Question

Sodium, which has an atomic number of 11, will react with chlorine, which has an atomic number of 17. when these two atoms react, both become stable. to become stable, sodium will ____________, while chlorine will ____________.

Answer 1

Since all atoms favor reacting in a way that gives them the same valence electron configuration as a noble gas (the last column on the right of the periodic table), sodium will lose 1 electron, while chlorine will gain one electron.

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Answer 2

Explanation:

Atomic number of sodium is 11 and its electronic distribution is 2, 8, 1. Whereas atomic number of chlorine is 17 and its electronic distribution is 2, 8, 7.

As we known that in order to attain stability each element must have 8 electrons in its outer orbital. Therefore, in order to attain stability sodium will lose one electron and chlorine will tend to gain one electron.

As a result, an ionic bond will be formed between sodium and chlorine and hence, NaCl is formed.

Thus, we can conclude that sodium, which has an atomic number of 11, will react with chlorine, which has an atomic number of 17. when these two atoms react, both become stable. to become stable, sodium will lose, while chlorine will gain an electron.