Question

the larger of two numbers is 10 less than twice the smaller number. If the sum of the two numbers is 38, find the two numbers. Show how you got your answer?

Answer 1

x = larger number, y = smaller number

x + y = 38...because the sum of the numbers is 38
x = 2y - 10....larger one is 10 less then twice the smaller

now we will sub in 2y - 10 for x back into the first equation
x + y = 38
2y - 10 + y = 38
3y - 10 = 38...add 10 to both sides
3y = 38 + 10
3y = 48 ...divide both sides by 3
y = 48/3
y = 16

now sub 16 in for y back into either of the original equations and find x
x = 2y - 10
x = 2(16) - 10
x = 32 - 10
x = 22

so ur numbers are 16 and 22