Respuesta :
Each paper clip can be traded for three matches.
Each pencil can be traded for six paper clips which can be traded for (6 x 3 = 18) eighteen matches.
Two pencils and two paper clips are worth (2 x 18 + 2 x 3 = 36 + 6 = 42) which is greater than thirty-eight matches.
Therefore, Two pencils and two paper clips are worth thirty-eight matches.
Each pencil can be traded for six paper clips which can be traded for (6 x 3 = 18) eighteen matches.
Two pencils and two paper clips are worth (2 x 18 + 2 x 3 = 36 + 6 = 42) which is greater than thirty-eight matches.
Therefore, Two pencils and two paper clips are worth thirty-eight matches.
Answer:
Three pencils are worth greater than seventeen paper clips.
Step-by-step explanation:
Each paper clip can be traded for three matches.
Each pencil can be traded for six paper clips.
Three pencils are worth [tex]3\times6=18[/tex] paper clips.
So, the correct statement is - Three pencils are worth greater than seventeen paper clips.