Question

A ball is dropped from a cliff and has an acceleration of 9.8 m/s^2 how long will it take the ball to reach a speed of 24.5 m/s

Answer 1

Acceleration of ball (a) = 9.8 m/s^2 Speed (v) = 24.5 m/s Time (t) = Acceleration / Time = v / a = 24.5/9.8 = 2.5 s So it will take 2.5 seconds to reach that speed.

Answer 2

Answer:

Acceleration of ball (a) = 9.8 m/s^2 Speed (v) = 24.5 m/s Time (t) = Acceleration / Time = v / a = 24.5/9.8 = 2.5 s So it will take 2.5 seconds to reach that speed.

Explanation: