Question

Consider the polynomial 9x2 – 16. What is the value of ac? What is the value of b? What two numbers multiply to get ac and add to get b? The factored form of 9x2 – 16 is

Answer 1

9x² - 16 = (3x - 4) (3x + 4)
A      C

The value of ac together is 16(9x²) or 144x²

The value of B is zero, since there is no B (b is x, (note not x², but only 1 x))


hope this helps

Answer 2

The value of ac is -144, the value of a is 9, the value of b is 0, and the value of c is -16 and this can be determined by comparing the generalized quadratic equation with the given quadratic equation.

Given :

Polynomial  ---  $9x^2-16$  --- (1)

The generalized quadratic polynomial equation is given by:

$\rm ax^2 + bx + c = 0$   --- (2)

Comparing equation (1) with equation (2) in order to get the value of 'a' and 'c'.

a = 9

c = -16

So, the value of the product of 'ac' is:

$\rm ac = 9\times -16$

ac = -144

The value of b is 0 and this is determined by comparing equation (1) and equation (2).

Now, factorize the equation (1).

$=9x^2-16$

$=(3x)^2-4^2$

$=(3x-4)(3x+4)$

For more information, refer to the link given below:

https://brainly.com/question/11403474