Question

Math help plz!!!

There is an average of 3.5×10^−2 kilograms of dissolved salt in each liter of seawater. The South China Sea contains approximately ​ 9.88×10^18 ​ liters of seawater.

About how many kilograms of dissolved salt are in the South China Sea?

Enter your answer, in scientific notation, in the boxes.

__ x 10^__ kg

Please help and thank you!

Answer 1

Answer:

3.458 × 10¹⁷

Explanation:

We multiply the amount of salt per liter, 3.5×10⁻², by the amount of sea water in the South China Sea, 9.88×10¹⁸:

(3.5×10⁻²)(9.88×10¹⁸)

Multiplication is commutative; this means we can switch around the numbers we are multiplying:

(3.5×9.88)(10⁻²×10¹⁸)

Multiplying the numbers in the first set of parentheses, we have 34.58.

To multiply the powers of 10, we use the product property; it states that if we multiply powers that have the same base, we add their exponents:

10⁻²×10¹⁸ = 10⁻²⁺¹⁸ = 10¹⁶

This gives us 34.58 × 10¹⁶.  In scientific notation, the decimal must be behind the first non-zero digit; this gives us 3.458.  When we move the decimal again, we add 1 to the exponent; this gives us 3.458 × 10¹⁷

Answer 2

The kilograms of salt in the South China Sea is required.

The amount of salt in the South China Sea is $3.458\times 10^{17}\ \text{kg}$

The amount of salt in 1 liter of seawater is $3.5\times 10^{-2}\ \text{kg}$

$1\ \text{liter of seawater}=3.5\times 10^{-2}\ \text{kg of salt}$

The volume of seawater in the South China Sea is $9.88\times 10^{18}\ \text{L}$

$9.88\times 10^{18}\ \text{liters of seawater}=9.88\times 10^{18}\times 3.5\times 10^{-2}=3.458\times 10^{17}\ \text{kg}$

The amount of salt in the South China Sea is $3.458\times 10^{17}\ \text{kg}$

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