Question

84, 99, 88, 82, 95, 85

Myra's test scores are shown. She has one more test for the semester. What is the minimum score that she can make on her last test and have an average greater than 90?

Note: All scores are whole numbers and scores are not rounded

a. 95
b.96
c.97
d.98

Answer 1

(84+99+88+82+95+84+98)/7 = 90 , so 98, or D. 

Answer 2

Answer:

Option: d is the correct answer.

               d. 98

Step-by-step explanation:

The scores of Myra's test are as follows:

               84, 99, 88, 82, 95, 85

Let 'x' be the minimum  score that is obtained by Myra in the last test so that the average is greater than 90 marks.

i.e.

$\dfrac{84+99+88+82+95+85+x}{7}>90\\\\\\i.e.\\\\\\\dfrac{533+x}{7}>90\\\\\\i.e.\\\\\\533+x=90\times 7\\\\\\533+x>630\\\\\\x>630-533\\\\\\x>97$

Hence, the minimum score has to be 98.

(   Since, the scores are in whole number )