Question

A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

Answer 1

work done = force * distance moved (in direction of the force)

force= mass* acceleration 

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J

Answer 2

Answer:

58.1*(5.8*10^4)  =3,369,800 Joules. hope it helps