2(|x−3|)−4≥10
Step 1: Add 4 to both sides.2(|x−3|)−4+4≥10+42(|x−3|)≥14Step 2: Divide both sides by 2.2(|x−3|)2≥142|x−3|≥7Step 3: Solve Absolute Value.|x−3|≥7We know eitherx−3≥7orx−3≤−7x−3≥7(Possibility 1)x−3+3≥7+3(Add 3 to both sides)x≥10x−3≤−7(Possibility 2)x−3+3≤−7+3(Add 3 to both sides)x≤−4
the answer is
x≥10or x≤−4