Respuesta :
13.4 billion years is 3 times of the half-life, 4.47 billion years. So the Uranium-238 will go through three times of half decay. So the remain percentage will be 50%*50%*50%=12.5%.
Answer:
12.53 % of a sample of Uranium-238 will remain after 13.4 billion years.
Explanation:
The half life of the uranium-238 = [tex]t_{\frac{1}{2}}[/tex]=4.47 billion years
All the radioactive reaction are of first order kinetics. The rate constant and t half of the reaction are related as:
[tex]k=\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{4.47 \text{billion years}}=0.1550 (\text{billion years})^{-1}[/tex]
[tex]k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}[/tex]
where,
k = rate constant = [tex]0.1550 (\text{billion years})^{-1}[/tex]
t = time taken during radio decay = 4.47 billion years
[tex][A_o][/tex] = initial amount of the reactant = [tex]1.45\times 10^{-6}mol/L[/tex]
[A] = amount left left after time t.
[tex]\log \frac{[A]}{[A_o]}=-\frac{kt}{2.303}[/tex]
[tex]\frac{[A]}{[A_o]}=0.1253=\frac{12.53}{100}=12.53\%[/tex]
12.53 % of a sample of Uranium-238 will remain after 13.4 billion years.