[tex]x+1=0 \\ \\ x=-1 \\ \\ \pmb 1^{o} \\ \\ x\in (-\infty,-1) \\ \\ -5|x+1|=10 \\ \\ 5(x+1)=10 \\ \\ 5x+5=10 \\ \\ 5x=5 \\ \\ x=1 \not\in D \\ \\ \pmb 2^{o} \\ \\ x\in [-1, +\infty) \\ \\ -5|x+1|=10 \\ \\ -5(x+1)=10 \\ \\ -5x-5=10 \\ \\ -5x=15 \\ \\ x=-3 \not\in D \\ \\ x\not\in \Re[/tex]
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"Associate with people who are likely to improve you."