The hypotenuse of a 45-45-90 triangle measures 22 square root2 units. What is the length of one leg of the triangle?
![The hypotenuse of a 454590 triangle measures 22 square root2 units What is the length of one leg of the triangle class=](https://us-static.z-dn.net/files/de3/1a8e9f768f30539f8e679d93f8f5ab2e.png)
Answer:
The length of one leg is [tex]22\ units[/tex]
Step-by-step explanation:
we know that
In a [tex]45\°-45\°-90\°[/tex] right triangle the length of the two legs are equal
Let
x-----> the length of one leg
y----> the hypotenuse
Remember that
[tex]sin(45\°)=\frac{\sqrt{2}}{2}[/tex]
In this problem
[tex]sin(45\°)=\frac{x}{y}[/tex]
we have
[tex]y=22\sqrt{2}\ units[/tex]
substitute and solve for x
[tex]\frac{\sqrt{2}}{2}=\frac{x}{22\sqrt{2}}[/tex]
[tex]x=22\sqrt{2}(\frac{\sqrt{2}}{2})=22\ units[/tex]