Answer: pH is 0.34
Explanation: Moles can be calculated by using the formula:
[tex]\text{no of moles of } HNO_3}={\text{Molarity}\times {\text{Volume in L}}[/tex]
[tex]\text{no of moles}={2.88M}\times {0.365L}=1.05moles [/tex]
[tex]HNO_3\rightarrow H^++NO_3^_[/tex]
Moles of [tex]H^+[/tex] ions = 1.05
[tex]\text{no of moles of } Ca(OH)_2}={\text{Molarity}\times {\text{Volume in L}}[/tex]
[tex]\text{no of moles}={1.10M}\times {0.335L}=0.36[/tex]
[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]
Moles of [tex]OH^-[/tex] ions = [tex]2\times 0.36=0.73moles[/tex]
Thus 0.73 moles of [tex]Ca(OH)_2[/tex] will neutralize 0.73 moles of [tex]HNO_3[/tex] and (1.05-0.73)=0.32 moles of [tex]HNO_3[/tex] will be left.
Molarity of [tex]H^+=\frac{moles}{total volume in L}=\frac{0.32moles}{0.7L}=0.46M[/tex]
[tex]pH=-\log[H^+]=-\log[0.46]=0.34[/tex]
