In the wizard of oz, dorothy awakens in munchkinland where her house has been blown by a tornado. if the house fell from rest (after being released from the tornado) from a height of 3000 m, with what speed did it hit the wicked witch of the east when it landed? assume that the acceleration due to gravity in oz is 9.81 m/s2 .

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20-09-2017
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In the wizard of oz, dorothy awakens in munchkinland where her house has been blown by a tornado. if the house fell from rest (after being released from the tornado) from a height of 3000 m, with what speed did it hit the wicked witch of the east when it landed? assume that the acceleration due to gravity in oz is 9.81 m/s2 .

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W0lf93 W0lf93 · Answer 1 · 2017-10-02T12:34:03+02:00

v = 242.6 m/s Ignoring air resistance, the distance traveled under constant acceleration is 1/2 AT^2, so let's figure out how long it took for the house to fall 3000 m = 0.5 * 9.81 m/s^2 * T^2 Solve for T 6000 m = 9.81 m/s^2 * T^2 611.6208 s^2 = T^2 24.73097 s = T So the house fell for 24.73 seconds. Now just multiply to determine its speed at impact. v = 24.73 s * 9.81 m/s^2 v = 242.6 m/s