Question

Which of the following functions has the largest value when x = 4?

e(x) = x2 + 6x + 21
m(x) = 8x
v(x) = 31x

Answer 1

$e(4)=4^2+6 \times 4+21=16+24+21=61 \\ \\ m(4)=8 \times 4=32 \\ \\ v(4)=31 \times 4=124$

v(x) has the largest value when x=4.

Answer 2

Answer: $v(x)=31x$

Step-by-step explanation:

Given Functions: $e(x)=x^2+6x+21$

$m(x)=8x\\\\v(x)=31x$

At x=4

$e(4)=(4)^2+6(4)+21\\=16+24+21=61\\\\m(4)=8(4)=32\\\\v(4)=31(4)=124$

here we can see v(4) has the largest value of 124 at x=4 .

Therefore, $v(x)=31x$ is the function which has the largest value at x=4.