Question

The length of rectangle is 6 feet greater than the width. the perimeter is 40 ft. find the dimensions of the rectangle.

Answer 1

P=2(L+W)

if L is 6 great than W
L=6+W

and P=40

subsitute 40 for P and 6+W for l

40=2(6+W+W)
40=2(6+2W)
divide both sides by 2
20=6+2W
minus 6 both sides
14=2W
divide both sides by 2
7=W
W=7

sub back
L=6+W
L=6+7
L=13


the rectangle has a length of 13ft and width of 7ft