Question

What is the acceleration of an object with mass of 42.6 kg when an unbalanced force of 112 N is applied to it

Answer 1

The answer is 2.63m/s^2! You use the formula F=ma, 112 = 42.6(a), a= 2.63m/s^2.

Answer 2

Answer:

$2.63m/s^2$

Explanation:

To solve this problem we use Newton's second law, which establishes a relationship between mass, acceleration and force applied to an object.

$F=ma$

Where $F$  is the force, $m$ is the mass and $a$ is the acceleration. Because they ask us for acceleration, we clear for  $a$:

$a=\frac{F}{m}$

And since we have the following information:

$m=42.6kg$ and $F=112N$

the acceleration will be:

$a=\frac{112N}{42.6kg}$

$a=2.629m/s^2$≈ $2.63m/s^2$

The answer is that the acceleration of the object is $2.63m/s^2$