Question

A chemist needs to find out how large of a container would be required to contain the products of an ammonia decomposition. If 8.91 mol H2 are produced during the reaction, how many moles of N2 are produced?

Answer 1

the answer is 2.97 mol N2

Answer 2

Answer : The moles of $N_2$ produced are, 2.97 moles

Solution : Given,

Moles of $H_2$ = 8.91 moles

The balanced decomposition reaction of ammonia will be,

$NH_3\rightarrow 3H_2+N_2$

From the balanced reaction, we conclude that

When 2 moles of $NH_3$ decomposes to produce 3 moles of $H_2$ and 1 mole of $N_2$

If the moles of $H_2$ is 3 moles then the moles of $N_2$ produces = 1 mole

If the moles of $H_2$ is 8.91 moles then the moles of $N_2$ produces = $\frac{8.91moles}{3moles}=2.97moles$

Therefore, the moles of $N_2$ produced are, 2.97 moles