Question

Evaluate √7x(√x−7√7) please Show your Work thanks.

Answer 1

 expand by multiplying √7x⋅√x and √7x⋅7√7 

√7x(√x−7√7)=√7x⋅√x−√7x⋅7√7

You can make√7x into √7⋅√x

=√7⋅√x⋅√x−√7⋅√x⋅7⋅√7=√7⋅(√x)2−(√7)2⋅√x⋅7

since squaring and square roots are opposite, they cancel

=√7⋅x−7⋅√x⋅7=x√7−49√x
I hope the square root symbols worked. I had to copy and paste from word. Hopefully this is what you needed!

Answer 2

remember
$(\sqrt{a})(\sqrt{b})=\sqrt{ab}$


first distribute

$\sqrt{7x^2}-7\sqrt{49x}=$
$(\sqrt{x^2})(\sqrt{7})-7(\sqrt{49})(\sqrt{x})=$
$x\sqrt{7}-7(7)\sqrt{x}=$
$x\sqrt{7}-49\sqrt{x}$ is simlified form
to evaluate, we would need a value for x