[tex]\bf \displaystyle \int~(x^2+1)cot(x^3+3x)\cdot dx\\\\
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\stackrel{substitution}{u=x^3+3x}\implies \cfrac{du}{dx}=3x^2+3\implies \cfrac{du}{dx}=3(x^2+1)
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\cfrac{du}{3(x^2+1)}=dx\\\\
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\displaystyle \int~\underline{(x^2+1)} cot(u)\cdot \cfrac{du}{3\underline{(x^2+1)}}\implies \cfrac{1}{3}\int~cot(u)\cdot du
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\cfrac{1}{3}( ln|sin(u)|)+C\implies \cfrac{ln|sin(x^3+3x)|}{3}+C[/tex]