Answer:
All real numbers.
Step-by-step explanation:
To solve for x:
Simplify: [tex]4(x+1)\leq 4x+3[/tex]
Expand : [tex]4(x+1)=4x+4[/tex] we have,
[tex]4x+4\leq 4x+3[/tex]
Subtract 4 from both the sides,
[tex]4x+4-4\leq 4x+3-4[/tex]
Simplify we get,
[tex]4x\leq 4x-1[/tex]
Subtract [tex]4x[/tex] from both the sides,
[tex]4x-4x\leq 4x-1-4x[/tex]
On simplifying we get,
[tex]0\leq -1[/tex], which is false ∀ x∈[tex]R[/tex]
