Question

Five people come to a party and shake hands with each other if each person shakes the hand of every other person how many handshakes occur

Answer 1

Let's name each person as A,B,C,D,E
A-B
A-C
A-D
A-E
A does 4 handshakes
B-C
B-D
B-E
B does 3 handshakes
C-D
C-E
C does 2 handshakes
D-E
D does 1 handshake

In total= 4+3+2+1
            = 10 handshakes 

Answer 2

Answer:

10 handshakes

Step-by-step explanation:

Five people come to a party and shake hands with each other.

This means 5 people shakes the hand of other 4 persons.

We use the formula $\frac{n(n-1)}{2}$

Where n is number of people

$\frac{5(5-1)}{2}$

$\frac{20}{2}$

= 10

10 handshakes would occur.