Question

A gas occupying a volume of 25 ft3 weighs 3.5 lbf on the moon, where the acceleration of gravity is 5.47 ft/s2. determine its weight, in lbf, and density, in lb/ft3 , on mars, where g = 12.86 ft/s2 .

Answer 1

8.23 lbf,0.824 lb/ft3

Answer 2

a. The weight of this gas on Mars is equal to 8.2304 lbf.

b. The density of this gas on Mars is equal to 0.0256 $lb/ft^3$.

Given the following data:

• Volume of gas = 25 $ft^3$

• Weight of gas on Moon = 3.5 lbf.

• Acceleration of gravity on Moon = 5.47 $ft/s^2$

• Acceleration of gravity on Mars = 12.86 $ft/s^2$

a. To determine the weight of this gas on Mars:

First of all, we would calculate the mass of this gas.

The formula for weight.

Mathematically, the weight of a gas is given by this formula;

$Weight = mg$

Where:

• m is the mass of the gas.

• g is the acceleration due to gravity.

Substituting the given parameters into the formula, we have;

$3.5 = mass \times 5.47\\ \\ Mass =\frac{3.5}{5.47}$

Mass = 0.64 lb.

For the weight on Mars:

$Weight = 0.64 \times 12.86$

Weight = 8.2304 lbf.

b. To determine the density of this gas on Mars:

Mathematically, the density of a gas is given by the formula;

$Density = \frac{mass}{volume} \\ \\ Density = \frac{0.64}{25}$

Density = 0.0256 $lb/ft^3$

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