The distance traveled during the reaction time is
d₁ == (20 m/s)*(0.50 s) = 10 m
The deceleration is 6.0 m/s²
The distance, d₂, traveled until the car comes to a complete stop is given by
(20 m/s)² - 2*(6.0 m/s²)*(d₂ m) = 0
d₂ = 400/12 = 33.333 m
The total distance traveled before the car comes to rest is
d₁ + d₂ = 10 + 33.333 = 43.333 m
Because 43.333 m is less than 50 m, the car will not hit the object.
Answer:
The car comes to a stop before reaching the object. It will not hit the object.