Question

How do you divide scientific notation problems like this: 0.00053 ÷ 29?

Answer 1

you got to remember
$\frac{x^m}{x^n}=x^{m+n}$

first write them in scienfitic notation
0.00053=$5.3*10^{-4}$
29=$2.9*10^1$


so
$\frac{0.00053}{29}=$
$\frac{(5.3)(10^{-4})}{(2.9)(10^1)}=$
$(\frac{5.3}{2.9})(\frac{10^{-4}}{10^1}=$
$(1.8275862068965517241379310344828)(10^{-4-1})=$
$(1.8275862068965517241379310344828)(10^{-5})=$
$1.8275862068965517241379310344828*10^{-5}$

that's the answer