Respuesta :
Look, that:
[tex]\dfrac{1}{4} = \dfrac{2}{8} \\ \\ \dfrac{7}{16}= \dfrac{3.5}{8} \\ \\ \dfrac{1}{8} \\ \\ \dfrac{3}{16}=\dfrac{1.5}{8}[/tex]
(in second and fourth fractions just divide nominator and denominator by 2). Greater than 3/8 is this fraction, which has nominator greater than 3. It is 3.5/8. So 7:16 - answer b)
[tex]\dfrac{1}{4} = \dfrac{2}{8} \\ \\ \dfrac{7}{16}= \dfrac{3.5}{8} \\ \\ \dfrac{1}{8} \\ \\ \dfrac{3}{16}=\dfrac{1.5}{8}[/tex]
(in second and fourth fractions just divide nominator and denominator by 2). Greater than 3/8 is this fraction, which has nominator greater than 3. It is 3.5/8. So 7:16 - answer b)
[tex]\frac{3}{8} \\ \frac{1}{4}=\frac{1 \times 2}{4 \times 2}=\frac{2}{8} \\
3 \ \textgreater \ 2 \Rightarrow \frac{3}{8} \ \textgreater \ \frac{2}{8} \Rightarrow \frac{3}{8}\ \textgreater \ \frac{1}{4} \\
\hbox{not greater} \\ \\
\frac{3}{8}=\frac{3 \times 2}{8 \times 2}=\frac{6}{16} \\
\frac{7}{16} \\
6\ \textless \ 7 \Rightarrow \frac{6}{16} \ \textless \ \frac{7}{16} \Rightarrow \frac{3}{8} \ \textless \ \frac{7}{16} \\
\hbox{greater}[/tex]
[tex]\frac{3}{8} \\ \frac{1}{8} \\ 3\ \textgreater \ 1 \Rightarrow \frac{3}{8} \ \textgreater \ \frac{1}{8} \\ \hbox{not greater} \\ \\ \frac{3}{8} =\frac{3 \times 2}{8 \times 2}=\frac{6}{16} \\ \frac{3}{16} \\ 6\ \textgreater \ 3 \Rightarrow \frac{6}{16} \ \textgreater \ \frac{3}{16} \Rightarrow \frac{3}{8} \ \textgreater \ \frac{3}{16} \\ \hbox{not greater}[/tex]
The answer is B.
[tex]\frac{3}{8} \\ \frac{1}{8} \\ 3\ \textgreater \ 1 \Rightarrow \frac{3}{8} \ \textgreater \ \frac{1}{8} \\ \hbox{not greater} \\ \\ \frac{3}{8} =\frac{3 \times 2}{8 \times 2}=\frac{6}{16} \\ \frac{3}{16} \\ 6\ \textgreater \ 3 \Rightarrow \frac{6}{16} \ \textgreater \ \frac{3}{16} \Rightarrow \frac{3}{8} \ \textgreater \ \frac{3}{16} \\ \hbox{not greater}[/tex]
The answer is B.