Respuesta :
a - quantity tickets for adults. It costs 5a dollars
c - quantity tickets for children. It costs 2c dollars.
There were 1750 tickets sold, so a+c=1750$. That's mean a = 1750 - c.
Total: 7 100$, That's mean 5a + 2c = 7 100. Substitute now 1750-c instead "a" :
5(1750-c) + 2c = 7100
8750 - 5c + 2c = 7100
-3c = -1650 |divide (-3)
c = 550
So a =1750 -c = 1750 - 550 = 1200
There were sold 1200 tickets for adults and 550 tickets for children
c - quantity tickets for children. It costs 2c dollars.
There were 1750 tickets sold, so a+c=1750$. That's mean a = 1750 - c.
Total: 7 100$, That's mean 5a + 2c = 7 100. Substitute now 1750-c instead "a" :
5(1750-c) + 2c = 7100
8750 - 5c + 2c = 7100
-3c = -1650 |divide (-3)
c = 550
So a =1750 -c = 1750 - 550 = 1200
There were sold 1200 tickets for adults and 550 tickets for children
The number of children's ticket sold for the play is 550.
What are the linear equations that represent the question?
5a + 2b = $7100 equation 1
a + b = 1750 equation 2
Where:
a = adult tickets sold
b = number of children's ticket sold
What is the number of children's ticket sold?
In order to determine the answer, multiply equation 2 by 5:
5a + 5b = 8750 equation 3
Subtract equation 3 from equation 1
3b = 1650
Divide both sides by 3
b = 550
To learn more about simultaneous equations, please check: https://brainly.com/question/25875552
