Question

Factor the following binomial completely.
16 x squared minus 1

Answer 1

Again, let's use the difference of squares.

a^2-b^2= (a+b)(a-b)

16x^2-1
(4x+1)(4x-1)

Final answer: (4x+1)(4x-1)

Answer 2

This is an example of difference of squares factoring

Here is how you can deal with it;;;

$16x^2-1=(4x)^2-1^2$

the first term is the square of 4x and the second one is the square of 1

then, you can write:

$[(4x)-1]*[(4x)+1]=[4x-1][4x+1]$


Done...

Hope you got the idea