Question

. If the combustion of 45.0 g of methane (natural gas) releases 2498 kJ of heat energy, how much heat
energy in kJ would be released by combustion of 1.55 kg of methane?

Answer 1

45g ---> 2498kJ
1.55g ----> ?kJ
 Answer: (1.55x2498)/45 approx 86.04 (kJ)

Answer 2

Answer:

8.60 x 10⁴ kJ

Explanation:

The energy released per gram of methane is first calculated:

(2498kJ)/(45.0g) = 55.5 kJ/g

The heat released by the combustion of 1.55 kg of methane is then calculated:

(55.5kJ/g)(1.55kg)(1000g/kg) = 86025kJ

To three significant digits, the answer is 8.60 x 10⁴ kJ.