A shipment of sugar fills 2 1/5 containers. If each container holds 3 3/4 tons of sugar, what is the amount of sugar in the entire shipment?

Respuesta :

2 1/5 * 3 3/4 =
11/5 * 15/4 =
33/4 =
8 1/4 (or 8.25) tons <==

Answer: [tex]8\dfrac{1}{4}\text{ tons }[/tex]

Step-by-step explanation:

Given : A shipment of sugar fills [tex]2\dfrac{1}{5}[/tex] containers.

it can be written as [tex]\dfrac{11}{5}[/tex]

Amount of sugar each container holds = [tex]3\dfrac{3}{4}[/tex] tons

it can be written as [tex]\dfrac{15}{4}[/tex]

Now, the amount of sugar in the entire shipment will be :_

[tex]\dfrac{15}{4}\times\dfrac{11}{5}=\dfrac{33}{4}=8\dfrac{1}{4}\text{ tons }[/tex]

Hence, the amount of sugar in the entire shipment =[tex]8\dfrac{1}{4}\text{ tons }[/tex]