Question

What is the slope of any line parallel to the line 8x+9y=3 in standard (x,y) coordinate plane?

Answer 1

8x + 9y = 3
9y = -8x + 3
y = -8/9x + 1/3...the slope here is -8/9. A parallel line will have the same slope....so any line parallel to 8x + 9y = 3 will have a slope of -8/9

Answer 2

The slope of any line parallel to the line 8x+9y=3 in standard (x,y) coordinate plane is $-\frac{8}{9}$.

We write 8x + 9y = 3 in the slope intercept form.

$8x + 9y = 3\\9y=-8x+3\\y=-\frac{8}{9}x+\frac{3}{9}$

The slope of the line 8x + 9y = 3 is = $-\frac{8}{9}$.

We know that the slope of parallel lines are same.

So the slope of any line parallel to the line 8x+9y=3 in standard (x,y) coordinate plane is $-\frac{8}{9}$.

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