Question

A man jogs at a speed of 1.6 m/s. His dog
waits 1.8 s and then takes off running at a
speed of 2.7 m/s to catch the man.
How far will they have each traveled when
the dog catches up with the man?
Answer in units of m.

Answer 1

I believe it is
1.6x=2.7(x-1.8)
1.1x=2.7*1.8
x~4.4
4.4*1.6
~7.1m