Respuesta :
Answer:
24.5 g
Explanation:
The first thing to do here is to write a balanced chemical equation that describes this decomposition reaction
2KClO3(s)→2KCl(s)+3O2(g)↑⏐
Notice that it takes 2 moles of potassium chlorate to produce 3 moles of oxygen gas.
This means that if you know how many moles of oxygen gas were produced by the reaction, you can backtrack and use this 2:3 mole ratio to figure out how many moles of potassium chlorate underwent decomposition.
Now, STP conditions, which were probably given to you as a pressure of 1 atm and a temperature of 0∘C, are characterized by the fact that one mole of any ideal gas occupies 22.4 dm3 -- this is known as the molar volume of a gas at STP.
Use this value to calculate how many moles of oxygen gas were produced by the reaction
6.72dm3⋅ mole O222.4dm3=0.30 moles O2
This means that the decomposition reaction consumed
0.30moles O2⋅2amoles KClO33moles O2=0.20 moles KClO3
Now all you have to do is use the molar mass of potassium chlorate to calculate how many grams would contain this many moles
0.20moles KClO3⋅122.5 g1mole KClO3=∣∣ ∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯aa24.5 gaa∣∣−−−−−−−−−−
24.5 g
Explanation:
The first thing to do here is to write a balanced chemical equation that describes this decomposition reaction
2KClO3(s)→2KCl(s)+3O2(g)↑⏐
Notice that it takes 2 moles of potassium chlorate to produce 3 moles of oxygen gas.
This means that if you know how many moles of oxygen gas were produced by the reaction, you can backtrack and use this 2:3 mole ratio to figure out how many moles of potassium chlorate underwent decomposition.
Now, STP conditions, which were probably given to you as a pressure of 1 atm and a temperature of 0∘C, are characterized by the fact that one mole of any ideal gas occupies 22.4 dm3 -- this is known as the molar volume of a gas at STP.
Use this value to calculate how many moles of oxygen gas were produced by the reaction
6.72dm3⋅ mole O222.4dm3=0.30 moles O2
This means that the decomposition reaction consumed
0.30moles O2⋅2amoles KClO33moles O2=0.20 moles KClO3
Now all you have to do is use the molar mass of potassium chlorate to calculate how many grams would contain this many moles
0.20moles KClO3⋅122.5 g1mole KClO3=∣∣ ∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯aa24.5 gaa∣∣−−−−−−−−−−
Answer : The mass of potassium chlorate is, 102.125 grams
Explanation:
Potassium chlorate is a compound that contains potassium, chlorine and oxygen atom. The molecular formula potassium chlorate is, [tex]KClO_3[/tex]
From the molecular formula potassium chlorate we conclude that, there are 1 atom of potassium, 1 atom of chlorine and 3 atoms of oxygen.
The mass of 3 oxygen atom = 3 × 16 = 48 g
The molar mass of potassium chlorate = 122.55 g/mole
As, 48 gram of oxygen present in 122.55 grams of potassium chlorate
So, 40 gram of oxygen present in [tex]\frac{40}{48}\times 122.55=102.125[/tex] grams of potassium chlorate
Therefore, the mass of potassium chlorate is, 102.125 grams
