Respuesta :
Direct variation:
[tex]y=kx^2[/tex]
y - the distance, x - the time
The object falls 144 feet in 3 seconds.
[tex]144=k \times 3^2 \\ 144=9k \\ k=\frac{144}{9} \\ k=16 \\ \Downarrow \\ y=16x^2[/tex]
The object falls y feet in 17 seconds.
[tex]y=16 \times 17^2 \\ y=16 \times 289 \\ y=4624[/tex]
In 17 seconds the object will fall 4624 feet.
[tex]y=kx^2[/tex]
y - the distance, x - the time
The object falls 144 feet in 3 seconds.
[tex]144=k \times 3^2 \\ 144=9k \\ k=\frac{144}{9} \\ k=16 \\ \Downarrow \\ y=16x^2[/tex]
The object falls y feet in 17 seconds.
[tex]y=16 \times 17^2 \\ y=16 \times 289 \\ y=4624[/tex]
In 17 seconds the object will fall 4624 feet.
Question
This is a relatively close question, and I have tried multiple times. Can you help?
The distance an object falls when dropped from a tower varies directly as the square of the time it falls. If the object falls 144 feet in 3 seconds, how far will it fall in 18 seconds?
Answer: The one below is correct.