Respuesta :
x=0 is trivial solution. (since all terms have variable x)
Now divide both sides by x, you have 5x = -125
Now divide both sides by 5;
x = -125/5 = -25
So answer is x = 0 or -25.
Now divide both sides by x, you have 5x = -125
Now divide both sides by 5;
x = -125/5 = -25
So answer is x = 0 or -25.
[tex]\sf 5 x^{2} =-125x[/tex]
Divide x on both sides
[tex]\sf\frac{5 x^{2} }{x} = \frac{-125x}{x} [/tex]
Simplify that
[tex]\sf 5x=-125[/tex]
Divide by 5 on both sides
[tex]\sf\frac{5x}{5} = \frac{-125}{5} [/tex]
Simplify that
[tex]\sf x=-5[/tex]
One of your final answer will be:
[tex]\bf{\huge{\boxed{x=-5}}}[/tex]
But if you notice, we have x on both sides and it is doing multiplication. So another answer would be:
[tex]\bf{\huge{\boxed{x=0}}}[/tex]
And so your two answers are:
[tex]\bf{\huge{\boxed{x=0,-5}}}[/tex]
Divide x on both sides
[tex]\sf\frac{5 x^{2} }{x} = \frac{-125x}{x} [/tex]
Simplify that
[tex]\sf 5x=-125[/tex]
Divide by 5 on both sides
[tex]\sf\frac{5x}{5} = \frac{-125}{5} [/tex]
Simplify that
[tex]\sf x=-5[/tex]
One of your final answer will be:
[tex]\bf{\huge{\boxed{x=-5}}}[/tex]
But if you notice, we have x on both sides and it is doing multiplication. So another answer would be:
[tex]\bf{\huge{\boxed{x=0}}}[/tex]
And so your two answers are:
[tex]\bf{\huge{\boxed{x=0,-5}}}[/tex]